How do you define this measure in pure mathematical terms? You cannot use probability, because probability is physics (unless you find a sound mathematical definition of probability) — Mephist
Will someday be falsified', is not the same as 'has been falsified'. The falsification is what determines the faults, demonstrating the weaknesses of the theory, showing us where improvement is needed. There is no point in dismissing theories which have not yet been falsified, because we would not know what needs to be improved. That's the scientific method, observations which are inconsistent with what the theory predicts reveal the faults in the theory. But until those inconsistent observations come about, we don't know where the weaknesses of the theory lie. — Metaphysician Undercover
If you cannot see that the truth of this statement indicates that the theories have been falsified, then I'm afraid your denial is beyond hope. — Metaphysician Undercover
But instead of facing this fact, that the theories are wrong, someone has dreamed up a name "dark matter", and they attribute the fact that the theories are wrong to this mysterious thing, "dark matter". Why not just call it like it is, "the theories are wrong", dump the theories, and the "dark matter" which the theories necessitate because they're wrong, and get on with producing a new theory which doesn't make this mistake? — Metaphysician Undercover
Well, if the universe had no beginning then the past is infinite. So here we have the past as negative infinity as that's what you mean using the integers. Now consider the now to be any number on the integer number line: -3567, -9, 0, 1, 2019, etc. How do we reach these points? We'd have to pass through a positive infinity of time to reach these points. Now, is that possible? Of course not. Why? Think of the positive infinity {0, 1, 2, 3,...}. Can we pass through this positive infinity of time to reach any point that can be considered the present? Impossible, right? There has to be a beginning. It's not turtles all the way down. — TheMadFool
One way to define "constructive physics" is simply to say, "it uses constructive mathematics". But definitions of the latter sometimes arise principally from avoiding the LEM. Another tack is to avoid non-computable numbers. Or simply to state that experiments must be conclusive in a reasonable finite amount of time. I'm not sure what you two are referring to here. But I haven't read all the thread. — jgill
You cannot test if it is countable or not with physical experiments limited in time (how do you know that you don't get the same results again after a — Mephist
Constructive physics (constructivist logic) can ASSUME the existence of a function that you can call "random" (whatever it means: it's an axiomatic theory), representing a physical process. Only that you cannot DERIVE or COMPUTE this function. You have to assume it as an axiom of the theory. The point is that this is allowed by the logic because you cannot introduce inconsistencies in this way! — Mephist
i — Mephist
you cannot count on the fact that you always get the same output for the same input with absolute certainty: you get results that are statistically determined, but not deterministic. — Mephist
(fishfry: how did you post that graph? Are you a forum subscriber?) — jgill
There are two major zeros, and two minor zeros, to account for postive/negative and negative/positive.
One zero implies a positive bias, so I'd agree with TheMadFool. — Qwex
Hindus or Buddhists certainly wouldn't. — Wayfarer
It's not valid to write ... -> -5 as '...' is undefined then -5 is also undefined. — Devans99
Anything existing in time forever is impossible. It would have no initial state so no subsequent states — Devans99
That's not an example at all. We know a lot about dark matter, that's why we can name it. — Metaphysician Undercover
Similarly fishfry has his own speculative narrative built up from his interpretation of the facts (and for some reason is even more inordinately sure of himself). — Baden
So, genuine concern over a genuine issue or poking the market for profit? Mixed bag at best. — Baden
I did say "either that or there must be, at least, two kind/types of zeros" Are you implying -0 is not the same as +0? — TheMadFool

However notice the pattern. as x approaches positive infinity, 1/x approaches Zero from the positive side AND as y approaches negative infinity, 1/y approaches Zero from the negative side. — TheMadFool
Note that negative/positive of zero is zero i.e. -0 = +0 = 0. — TheMadFool
Short answer: for a finite experiment, "a priori" probabilities are simply functions that count the total number of possible results, "assuming" that each result has the same "probability" (yes, that's a circular definition: no formal definition of what "probability" is, even using ZFC set theory). — Mephist
No, in QM the pattern is NOT computable: the pattern is NOT predictable from the theory, so you DON'T NEED any computable function to predict it! — Mephist
Yes, EXACTLY! — Mephist
It's impossible for it to be, as you say, turtles all the way down because we're at a particular position in the sequence, right? There must be an ordinal number, as in nth number, that marks our position in the sequence. What is that number? There is none as I illustrated with the various ways the set of integers Z can be written. — TheMadFool
Another way to look at it would be that every number in the sequence of integers corresponds to the ordinal number infinity itself; — TheMadFool
after all we can only reach it after "beginning" at negative infinity by completing an infinite number of steps. It's my humble opinion that the infinite regress technique basically relies on the inability to complete an supertask as this is; to "begin" at negative infinity and reach any finite position in the sequence is impossible. — TheMadFool
She's following a classic toxic female script.
— fishfry
What is that and why is this perspective not sexist? — frank
I didn't realize the question would be hi-jacked in this way. — frank
Discuss the issue raised in the OP or step off, ok? — frank
Can you change your sex? I think so. — Bartricks
I didn't answer to this yet, so I'll do it now.
In general, category theory can be used to represent formal logic systems and their interpretations, in the obvious way: an interpretation is a functor from a category representing the language to a category representing the model ( https://en.wikipedia.org/wiki/Categorical_logic ). — Mephist
The vectors of this Hilbert space are the wave functions (not observable).
Observables are represented by Hermitian operators on the Hilbert space.
And the results of experiments (the numbers corresponding to the measured quantities) are the eigenvalues o these Hermitian operators.
(P.S. it's impossible to understand how it works from this description, but that's the way it is, if you want to be mathematically accurate) — Mephist
No, I didn't say you can calculate anything. You can calculate the magnetic moment of the electron in quantum electrodynamic with arbitrary precision, but only in theory (because the number of operations necessary grows exponentially with the number of calculated decimals), — Mephist
But I wanted to point out that there are parts of QM that are in some sense "mathematically perfect". Meaning: there are a finite set of atoms corresponding to all the possible combinations of electrons' orbitals up to a certain number of electrons (82 stable elements? I don't remember). And that ones are "perfect shapes", in the sense that two of them of the same type are exactly the same shape, like two squares. Usually (before QM) physics was made of objects that only corresponded to mathematical objects in an approximate way (orbits of planets for example), but if you looked carefully enough, every object in the physical world was different, and different from the mathematical object that represented it.
Atoms, and particles in QM in general, are different: they are "digital" (quantized) and not "analogical" shapes. So, in some sense, they are "perfect" (mathematical?) objects. — Mephist
It doesn't make sense that you would have assigned the symbol "2" to something and you know absolutely nothing about this thing which you have assigned the symbol to. — Metaphysician Undercover
So probably you mean the bitstreams that contain an infinite amount of information (not obtainable as the output of a finite program). There is no way to prove that such strings exist using a formal logic system (even using ZFC): — Mephist
OK I'll stop arguing about intuitionism. But I think you didn't get my point here, so let me try one last time: — Mephist
Cantor's theorem is valid in intuitionistic logic, but we know that intuitionistic real numbers are countable. In fact the theorem says: forall countable lists, there is an element that is not in the list, and we know that the set of elements missing from the list is countable because the list of all strings is countable.
Now you read the same theorem in ZFC and you interpret it as "there is an uncountable set of elements missing from the list". How do you know that the set of missing elements is uncountable? I mean: the symbolic expression of the theorem is the same, and the interpretation of the symbols is the same. How can you express the term "an uncountable set" in a language containing only the quantifiers "forall" and "there exists one" ?
And if there is no uncountable set of missing real numbers, there are no holes to fill.. — Mephist
For the first part of the question, I guess your question is how do you say "a finite random sequence" in intuitionistic logic. You can't! (at the same way as you can't do it in ZFC: the axiom of choice does not say "random" function). If the sequence is finite it is always computable, so you can say "there exist a finite sequence of numbers" ( the same as in ZFC ).
There is a definition of randomness as "a sequence that is not generated by a program shorter than the sequence itself" (lots of details missing, but you can find it on the web), but this is about the information content and not about the process used to choose the elements of the sequence.
About the bitstrings that aren't computable: all finite bitstrings are computable of course. So probably you mean the bitstreams that contain an infinite amount of information (not obtainable as the output of a finite program). There is no way to prove that such strings exist using a formal logic system (even using ZFC): we can interpret the meaning of Cantor's theorem in that way, and maybe there is such a thing in nature, but you cannot prove it with a finite deterministic formal logic system. — Mephist
All infinite causal regresses are impossible — Devans99
Z = {...-3, -2, -1, 0, 1, 2, 3,...} or Z = {...-4, -3, -2, -1, 0, 1, 2, 3, 4,..} or Z = {...-2, -1, 0, 1, 2,..} — TheMadFool
Using the infinity of integers doesn't succeed in solving the problem that there is no first fine-tuner. — TheMadFool
I want to know what the symbols are being used for. If you assert that the symbol "2" represents an object, I want a clear description of that object, so that I can recognize it when I apprehend it, and use the symbol correctly. — Metaphysician Undercover
Pascal's Wager is relevant because you have to decide to believe something because if you don't, you're screwed. — Carolyn Young
An infinite regress of fine tuner’s is impossible* — Devans99
But, hey! We got the Super Bowl and Twinkies, right? — Noah Te Stroete
Algebra makes the same mistake as set theory, assuming that a symbol represents an object. — Metaphysician Undercover
I believe humans lack the capacity to organize any significant conspiracy that wouldn’t result in their jailing or demise. People have consciences, differing wants, motives, and fears, that any cabal is doomed from the outset. — NOS4A2
