Clarification sought: zero is an even number Bear with me, everybody, if I'm always about six replies behind; I'm trying to keep up...
I understand the points made about the cardinality of the null set, because of course the null set does indeed contain one member - itself - and I should have kept that more clearly in mind. But my understanding (probably incorrect!) is that the null set is treatable as having cardinality 1 only in the special context of establishing a purely logical definition of the series of natural numbers.
Outside of that context, once we begin to talk about bundles of objects, relationships, and all of that exciting stuff, the cardinality of the null set assumes a value of 0 to make its properties consistent with those which we expect from the series of natural numbers as a whole. But that's something I'm not at all clear about: when the null set should or should not be counted among the cardinality of a set. For example, {x,y,z} has cardinality 3. The null set is not counted. But its power set has a cardinality of 8 and the null set IS counted.
Moving on, is it meaningful to say that we can divide into 2 equal subsets a set which contains only 1 member? And if it is, in the case of the null set, how to resolve the paradox that division by 2 yields 3 subsets of equal cardinality (if we are to stipulate a remainder of 0)? Is it not a condition of even parity that there should be only 2 subsets of the same cardinality?
Zero may well be an even number. But I sense something specious or at least simplistic about an argument such as "0 is even because 0 divided by 2 is 0, with a remainder of 0". It takes too many short cuts. It smells too much of selective attention. The traditional tests of even parity, applied to 0, turn up outcomes with anomalous features which do not occur in the case of any other natural number, and which require rationalisation. The anomalies are too glaring to be self-evidently consistent with the inductive nature of the series of natural numbers, and surely suggest a need for modification or re-definition of the tests.
In parenthesis, may I say, I like this forum. I have tried other forums before with, frankly, mixed results... I thank everybody for the courteous, intelligent and relevant replies posted.