Comments

  • Continuum does not exist


    Bull. You spout misinformation. Then you get explanations and ignore them, evidenced by asking questions that were already answered as you just go right ahead to re-spout. And you refuse to grasp the very simple fact that any explanation given you relies on previous concepts so that both the logical way and only downright practical way to know any of this is for you to start at page 1. If not trolling literally, it is trolling de facto. But do carry on ... it is amusing as pathetic comedy.
  • Continuum does not exist


    After many posts where I made no personal comments, I have correctly said that the poster is ignorant and confused about mathematics. And that is not gratuitous, especially as he persists to ignore the information and explanations given him. That is not analogous to your nearly immediately taking umbrage at corrections or suggestions for sharper formulation and then turning that to one of your sophomoric snipes. And, in this case, instead of responding to my substantive points about the terminology.
  • Continuum does not exist
    The formulation you gave doesn't mention that the ordering includes the standard ordering on w; it only mentions that every member of w is greater than -inf and less than inf.
    — TonesInDeepFreeze

    LOL. Pedants 'Я' us.
    fishfry

    That is not pedantic. The formuation you gave is literally very incorrect. I simply offered a correct formulation. For that, you reply petulantly (though not pedantically). Maybe, eventually, you'll get past nonsense like that.
  • Continuum does not exist
    Your obsessive pedantry is leading you astry.fishfry
    [emphasis added]

    Your penchant for making discussions personal leads you astray.
  • Continuum does not exist


    It's not pedantic but it is pedagogical.

    The key idea is sequences. And it is clear and concise to say:

    The domain is w+1 = wu{w} (or, taking liberties (w\{0})u{w}).

    But to go through cutting the real numbers down to positive integers and then adding points of infinity (moreover raising the pedagogical question of what exactly are "points of infinity") is an unnecessary detour and distracts from the insight of using sequences. Indeed, such things as dividing infinitely in a discussion such as this involves explicitly sequences. So the insight is that we have sequences not just on the ordinal w but also on ordinals such as w+1. Indeed that highlights that the range of such sequences may have other than ordinals (such as natural numbers) but that the domains are ordinals.

    You may use the lemniscate however you wish. But I wouldn't use it for w. Because it is a typical that uninformed people (I mean other posters, not you) are prone to use "infinity" as a catch-all for infinite sets. Indeed a point of infinity in the extended reals may be any set whatsoever except a real; doesn't even have to be an infinite set. That is, if we want to instantiate the extended real system, then we only need to choose two sets that are not themselves real numbers, then define the ordering and operations in the usual manner.

    But uninformed people don't distinguish between inf ('inf' read as the lemniscate) and the set of natural numbers. They regularly conflate inf ("infinity") with the set of natural numbers, which is an infinite set but not necessarily a point of infinity in the extended reals. So it is good pedagogically to use notation that doesn't lead to that conflation.

    On the other hand, making an analogy between w+1 and the positive extended reals is a nice idea. I would state it as only an analogy though.

    But of course, you are free to stipulate whatever definitions you like.
  • Continuum does not exist
    You mean the ordering:

    L u {<-inf n> | n in w} u {<n inf}> | n in w}, where L is the standard ordering on the natural numbers.

    The formulation you gave doesn't mention that the ordering includes the standard ordering on w; it only mentions that every member of w is greater than -inf and less than inf.
  • Continuum does not exist


    It's not a quirk. It's odd terminology, as far as I know; and the context here is not just points at infinity but sequences, and sequences are functions whose domain is an ordinal (or at least a set with a well ordering).

    The standard ordering on the real numbers is not a well ordering. So talking about points of infinity as in the domain of a sequence is confusing at best.

    The sequence is (I'm taking the liberty of starting at 1 rather than at 0):

    {<1 step-1> <2 step-2> ... <w final-state>}
  • Continuum does not exist


    You can call them whatever you want.

    (I see that there is a Wikipedia article that does use the terminology though. I don't usually reference the unreliable and haphazardly edited Wikipedia for mathematics.)

    But sequences are defined as having ordinals as the domain. That clarifies and can be widely referenced in the literature. And the extended reals of course is also a common notion. But the points of infinity in the extended reals are not ordinarily (if at all) understood as ordinals that are the domains of sequences.
  • Continuum does not exist
    Wrong. I explained the difference between them. Knowing the definition of 'the continuum' does not provide knowing the definition of 'continuous'.
    — TonesInDeepFreeze
    Do you mind elaborating?
    MoK

    What's to elaborate? I gave you the definitions of 'the continuum' and 'continuous function'. Meanwhile, a definition of 'a continuum' is not needed in this context, only 'the continuum'. Moreover there are different definitions of 'a continuum' in different contexts and they are way too technical for you. For purposes of the discussion at this juncture, 'the continuum' is sufficient. You ask for elaboration on concepts that depend on previous concepts that you refuse to learn. You won't even find out for yourself what a function is but you want people to explain mathematics to you.
  • Continuum does not exist


    I wouldn't, but suit yourself.
  • Continuum does not exist
    Thanks. So you simply extend the natural number to the extended natural number and resolve the problem of indexing.
    — MoK

    Yes exactly.
    fishfry

    Except that w is not called an "extended natural number".
  • Continuum does not exist


    Not "extended natural number".

    Rather the ordinal w+1 = wu{w}. That has been explained to you probably at least five times already.

    And there is no "problem of indexing". You're using the word 'indexing' incorrectly, as I've explained to you twice already.

    Any set can be indexed by being the range of a function. Indeed, trivially, any set is indexed by being the range of the identity function on the set.

    Your question might be whether a certain set can be indexed by w. By definition, any denumerable set can be indexed by w.

    But your question might go further: Can a set with an ordering on the set be isomorphic with w and the usual ordering on w. Of course, there are sets and orderings that are not isomorphic with one another. For example, in the current discussion, consider a set ordered

    1 2 3 ...

    That is isomorphic with the standard ordering on w.

    Consider a set ordered

    1 2 3 ... x

    That is not isomorphic with the standard ordering on w

    But it is isomorphic with the standard ordering on w+1.

    But these explanations are wasted on you because you won't actually look at a beginning reference on this subject so that your claims and questions aren't based on your confusions and ignorance.
  • Continuum does not exist
    My, argument here was for Dichotomy paradox.MoK

    Dichotomy schmicotomy. You mentioned 'average speed' and I gave you the formula.
  • Continuum does not exist
    1, 2, 3, 4, 5, 6, ...

    Is that not an infinite sequence?
    — fishfry
    That is an infinite sequence. I am however interested in the sequence first mentioned by Zeno in Dichotomy Paradox in which the infinite member exists. Each member of the above sequence is finite, so you cannot use the above sequence to give indexes to all members of the sequence in Dichotomy Paradox since the infinite member exists.
    MoK

    You're very confused and resistant to the explanations given you to cure your chronic confusion.
  • Continuum does not exist
    you cannot give indexes to all members of an infinite series.MoK

    Wrong. A series is a certain kind of function. Since it is a function, the range of the function is indexed by the domain of the function.

    Again, you're using mathematical terminology without a clue as to what it means. But that's okay. After, all, what is an Internet forum such as this good for if not to provide a platform for people who don't know what they're talking about to prolifically shoot their mouth off about it anyway?
  • Continuum does not exist
    Continuum is a continuous seriesMoK

    Wrong. A series is a certain kind of function. The continuum is not a function.

    He understands what continuous is if he understands what continuum is.MoK

    Wrong. I explained the difference between them. Knowing the definition of 'the continuum' does not provide knowing the definition of 'continuous'.
  • Continuum does not exist


    The arrow paradox is that the arrow does not move but that it moves.

    /

    Average speed is distance/time. In Zenos's paradox, both are finite.
  • Continuum does not exist
    Formally, a linear continuum is a linearly ordered set S of more than one element that is densely ordered, i.e., between any two distinct elements there is another (and hence infinitely many others), and complete, i.e., which "lacks gaps" in the sense that every nonempty subset with an upper bound has a least upper bound.
    — Wikipedia
    — fishfry
    Ok, that definition seems good and simple for tim wood. Thanks for providing the definition.
    MoK

    You're still conflating 'continuum' with 'continuous'. They are closely related concepts, but not the same concept. Also, the least upper bound property of the continuum already had been mentioned several times in this thread, so you had that information all along anyway.
  • Continuum does not exist
    I mean that there exists a point between two arbitrary points in which the between is defined as the geometrical mean.MoK

    (x+y)/2 is the arithmetical mean of {x y}, not the geometrical mean.
  • Continuum does not exist
    How could you index an infinite set of steps?MoK

    What does that mean? Ordinarily, "to index" means to make a set the range of a function, as the domain is the index set. The domain is the indexing set and the range is the indexed set.

    If there are denumerably many steps, then the steps may be indexed by the set of natural numbers. The set of natural numbers is the index set and the set of steps is the indexed set.

    What is the point of your question?
  • Continuum does not exist
    Could you calculate the speed in all infinite steps?MoK

    I don't know. First you would need to define "speed in all infinite steps".
  • Continuum does not exist
    I want to say that you could sweep all points of the continuum using that definition.MoK

    What definition of what? And what does "sweep" mean?
  • Continuum does not exist
    He asked for a definition of continuous and discrete in plain English. Could you please provide the definition in plain language without referring him to read a Calculus book?MoK

    My point was that he didn't ask for a definition of 'the continuum'. The takeaway for you is to not conflate 'the continuum' with 'continuous'.

    I didn't say that he needs to read a book. I said the definition is in chapter 1 of such books.

    'continuous function' is a mathematical notion, and best understood in its mathematical formulation, which is not complicated. But for informal explanations, one can do an Internet search on 'continuous function'. Such explanations include such mentions even as illustrative as "can draw the graph without lifting your pencil", which takes quite a bit of liberty from rigor but at least gives one a kind of mental picture.

    I mentioned that 'discrete' depends on context.
  • Continuum does not exist
    the Zeno paradox certainly threatens mathematicsMoK

    The speed of Achilles is 10meters/1second. The speed of Tortoise is 1meter/1000seconds.

    I applied mathematics to determine that, in the 100 meter race, Achilles will cross the finish line in 10 seconds and that Tortoise will cross the finish line in 100000 seconds.

    Then I called my bookie Zeus "The Moose" to place my 1000 euro bet on Achilles (favored 1000000000 to 1) and turned on the TV to watch the race on MSPN (the Mythic Sports Programming Network). After Achilles won, I called The Moose to collect. He started to say that my payoff is infinitesimal, so there's no way he can pay me; but I corrected him by telling him that there are no infinitesimals in the reals and that though the payoff is small, it is not infinitesimal. So he said he'd that he'd apply the fraction of a cent to my account. Meanwhile, there were a lot of Parmenideans who lost their togas betting on Tortoise.

    Seems math did a pretty good job. Maybe math threatens Zeno's paradox.
  • Continuum does not exist
    We say that the set is continuous if there is a point between any arbitrary pair of points.MoK

    Who is "we"? Other than you? What does "between" mean for sets in general? Or do you mean for real intervals? Usually, 'continuous' refers to functions. Perhaps there is an even more general notion of 'continuous sets', but we'd have to see it mathematically defined, in which case it's not going to be "there is a point between any two points".

    Why don't you look up some mathematics rather than just making up claims about it?
  • Continuum does not exist
    How about considering the point between two arbitrary points, namely a and b, to be mean, namely (a+b)/2?MoK

    We've been considering it at least fifty times already in this thread. What about it do you want to say?
  • Continuum does not exist
    please define the continuum for @tim wood in plain English?MoK

    He didn't ask for a definition of 'the continuum'. 'the continuum' is a noun. He asked for the distinction between 'continuous' and 'discrete'. 'continuous' and 'discrete' are adjectives.

    'the continuum' has been defined at least three times already in this thread.

    'continuous function' is the defined as usual in chapter 1 of any Calculus 1 textbook.

    Other senses of 'continuous' depend on context. And definitions of 'discrete' depend on context.
  • Continuum does not exist


    I am not a mathematician.
    Proof:

    Let Mx <-> x is a mathematician
    Let Rx <-> x produces results in mathematics
    Let t = TonesInDeepFreeze

    1. Ax(Mx -> Rx)
    2. Mt -> Rt {1}
    3. ~Rt
    4. ~Mt {1 3}
    QED CIA FBI DHS MLB NBA NFL NBC CBS ABC JFK LBJ FDR ETC
  • Continuum does not exist


    It's fine that you're talking about a question that's different from the one I replied to.
  • Continuum does not exist


    I have a good grasp of the some of the basics of set theory, but I am not very knowledgeable beyond those basics.

    Anyway, the idea of someone, who doesn't understand that the set of natural numbers is not a member of itself, trying to grapple with how ultrafilters play into proving the existence of hyperreals is ridiculous.
  • Continuum does not exist


    No one said anything about ZF.

    But if it is taken that there only finitely many things in what is designated as 'the real world', and it is regarded that there is no injection of an infinite set into a finite set, then the question is thereby settled, regardless of ZF; also, as far as I can tell, the other poster's call to Zeno's paradox or other supertask paradoxes would be unneeded.
  • Continuum does not exist


    (1) In open forums like this, there is usually more disinformation and confusion about mathematics than there is information and clarity. Instead, prolific cranks dominate, or discussions center on a few reasonable people trying to get a prolific crank to come to the table of reason.

    (2) There are no set theory experts in this thread (or, to my knowledge, posting in this forum).

    (3) Picking up bits and pieces of mathematics, hodge podge, is not an effective, not even a coherent, way to understand concepts that are built from starting assumptions and definitions. This thread itself is evidence of that.
  • Continuum does not exist


    That you have limited time for mathematics is all the more reason for not wasting that limited time in routes that lead to dead ends, misinformation and confusion.
  • Continuum does not exist


    What 1:1 map are you referring to? A 1:1 map from a real interval into points in space? A 1:1 map from a real interval into points of time? A 1:1 map from a real interval into a set of particles?

    I don't have much to say about those vis-a-vis Zeno's paradox. I'm only asking what your argument is that Zeno's paradox entails that there is not a map.
  • Continuum does not exist


    Please please please do not refer to AI bots for math proofs. They are so often incorrect. I've tried it a few times, and the bot gives clearly incorrect arguments - petitio principii - using as an assumption what it claims to be proving.

    And looking around at forums is also a disorganized and extremely poor way to learn mathematics.

    Get a book if you actually want to understand the material.
  • Continuum does not exist
    Start with one thing:

    Also BTW, "injection" is the word YOU are using.fishfry

    The poster asked about a "map into" as a "1:1 relation between".

    A word for that is 'injection'.

    An injection is a type of function between two sets.fishfry

    That's fine with me. And if you object to saying "injection" rather than "1:1 map" that's fine with me too. I'm not the one asking whether there is a 1:1 mapping (whether you wish to rule out calling that an 'injection') from the set of real numbers into whatever is designated by 'the real world'. Perforce, obviously, I'm not claiming that if there were such a 1:1 relation then its range would be a mathematical set.
  • Continuum does not exist
    First, again, I don't know what the poster means by "the real world" so I don't know what firm and clear notion there is of an injection from the set of real numbers into "the real world".

    Also, the argument "There are no relevant experiments regarding surrounding aspects of the reals, therefore there is no such injection" requires the premise, "If there is such an injection, then there are relevant experiments regarding surrounding aspects of the reals". But how would we rule out that there could be an injection but no relevant experiments regarding surrounding aspects of the reals, or that there could be an injection but no known relevant experiments regarding surrounding aspects of the reals?

    If the real numbers are instantiated in the real worldfishfry

    The question was about an injection. What is the definition of "instantiated in the real world"? Does it just mean that there is the range of an injection from the set of real numbers?

    If the real numbers are instantiated in the real world, then questions such as the axiom of choice and the Continuum hypothesis become subject to physical experiment.fishfry

    I don't know that that is the case. Moreover, cutting back to the question of an injection, I don't know that that the lack of someone thinking up an experiment would entail that there is no injection.

    Moreover, would entertaining that there is an injection from the set of natural numbers N into the real world entail that there must be some experiment to conduct?

    no physics postdoc has ever applied for a grant to study such mattersfishfry

    I don't know that that is true.

    such questions are so far beyond experimental investigation as to be meaningless.fishfry

    That might be the case. Indeed, even the question alone of the existence of an injection from the set of real numbers into "the real world" doesn't seem to me to have, at least so far, been given a firm and clear meaning.

    such questions are so far beyond experimental investigation as to be meaningless.fishfry

    That might be the case; I don't know. But I don't see that to entertain that there might be an injection entails that there must be an experiment to conduct. But again, the question of the existence of an injection from the set of real numbers into "the real world" doesn't seem to me to have, at least so far, been given a firm and clear meaning.

    Banach-Tarskifishfry

    I wouldn't think that to entertain that there is an injection from the set of reals into the real world entails that there is a physical version of Banach-Tarski. But again, the notion of such an injection is not definite enough for me to have much of a view anyway (as well as I'm not prepared to discuss details of Banach-Tarski).

    I surely don't have a strong opinion on the question of the existence of an injection from the set of real numbers into "the real world", but at least I would want to ponder whether the question is even even meaningful to either affirm or deny.
  • Continuum does not exist
    Supertasks have been used to show there isn't such a mapping for some cases.Relativist

    Zeno's paradox? Other? What arguments are you referring to that there is no injection from the set of real numbers into "the world"?
  • Continuum does not exist


    I don't opine here on that other question. But what do you mean by "maps into"? Do you mean "there is a function into" or do you mean "there is a one-to-one function into"? I surmise you mean the latter.
  • Continuum does not exist
    Therefore there is a gap between all pairs of distinct points of the continuum"Relativist

    It turned out that by 'gap' @MoK meant 'interval'. His thinking is hopelessly confused.

TonesInDeepFreeze

Start FollowingSend a Message