where exactly is "snow" denoted as snow and "white" denoted as white ? Because if not included within the T-sentence, then how can the T-sentence be formally correct ?" — RussellA
Do you mean this?:
Where in Tarski's example is snow denoted by 'snow' and white denoted by 'white'? If not in the example, then how can the schema be formally correct?
It's formally correct because it meets the criteria for formal correctness that Tarski specified, and which also are the usual criteria in mathematical logic.
Just to review:
Tarski is defining the adjective 'is true'. (More explicitly, for a given interpretation of a language, a definition of 'is true', or a definition of 'is true per the interpretation'.)
A definition of that adjective will be of the form (let M be an interpretation of the language):
'P' is true iff X
or
'P' is true per M iff X
where what X meets certain criteria (the criteria of formal correctness).
Tarski then says, 'P' itself will be X, so
'P' is true iff P
or
'P' is true per M iff P
And that is formally correct since it meets the criteria, and we show that it does
If one claims that it is not formally correct, then one needs to show that one of the criteria is not met. Saying, "How can it be formally correct if [whatever]?" doesn't have culpatory weight, any more in form than "How can an airplane fly if ducks have feet?"
Then the question you asked: Where is snow denoted by 'snow' and white denoted by 'white'? The answer, for formal languages, is in the interpretation of the language (the model for the language). The answer, for natural languages, is in the semantical assignments for words (usually per a dictionary or per the referential habits of speakers).
Even though the T-sentence "snow is white" is true IFF snow is white is given in a Metalanguage (ML), it is assumed that in a Metametalanguage (MML) snow has been named "snow" and white has been named "white". — RussellA
I don't see why they can't both be in the same metatheory. Or is there a liar paradox problem that comes up? If so, I'd like to see a proof:
Show if the metatheory gives an interpretation of the object theory and also a definition of truth, per that interpretation, of the language for the object theory, then that metatheory is inconsistent.
That doesn't seem right to me.
(Of course we know Tarski's theorem [simplified and roughly stated:] If if a theory has its own truth predicate, then the theory is inconsistent.
Therefore, white is a necessary condition for snow — RussellA
Tarski doesn't say that. It's your claim, I guess.
[There's redundancy in the rest of my post, because I want these points to come across in different phrasings:]
Indeed, Tarski doesn't even say that 'snow is white' is true. Rather, he is merely giving an instance from a definition of the adjective 'is true'. The example can work even with a false statement:
'Snow is black' is true iff snow is black.
The schema follows by form alone, and does not depend on what happens to be true or false or even necessarily true or necessarily false.
Even though the T-sentence "snow is white" is true IFF snow is white is given in a Metalanguage (ML), it is assumed that in a Metametalanguage (MML) snow has been named "snow" and white has been named "white". — RussellA
I don't see that the statement of the interpretation and the T-sentence can't be given in the same meta-theory.
Tarski says, "Let us suppose we have a fixed language L whose sentences are fully interpreted."
Yes, truth depends on interpretation of the language. A sentence can be true in one interpretation of the language and false in another interpretation of the language.
So, when we talk about the truth value of 'snow is white', we take it implicitly that some particular interpretation has been given.
Or we can make it explicit in this manner:
Let M and Q be interpretations for a language:
Examples:
Let the language have the constant symbols 'c' and 'd' and a 1-place predicate symbol 'F'.
Let M specify:
domain = {0 1}
'c' for 0
'd' for 1
'F' for {0}
So:
'Fc' is true per M iff Fc.
So:
'Fc' is true per M iff 0 is an element of {0}.
So:
'Fc' is true per M.
Now let Q specify:
domain = {0 1}
'c' for 1
'd' for 0
'F' for {1}
So:
'Fc' is true per M iff Fc.
So:
'Fc' is true per M iff 1 is an element of {1}.
So:
So 'Fc' is true per Q.
It is not assumed that we can only use an interpretation in which snow has been named 'snow' and white has been named 'white'. Rather, whatever 'snow' and 'white' name, the schema holds per that naming. If 'snow' named fire and 'white' named black, the schema would still hold. The schema does not dictate what 'snow' and 'white' should name. Indeed, what they name is interpretation-dependent. The schema works, per each interpretation. If a certain interpretation says 'snow' names fire and 'white' names black, then the schema still holds. My example of precipitation and chromaticity was conditional, and we may take that conditional as tantamount to an interpretation stipulating denotations. We could have stated the antecedent of the conditional so that 'snow' denotes fire and 'white' denotes black, thus tantamount to an interpretation stipulating different denotations from the usual ones, and the schema would still work.
It just happens that the "standard" interpretation (i.e. semantic assignments in English) has 'snow' standing for snow (precipitation ...) and 'white' standing for white (the chromaticity ...), so that's the most intuitive interpretation to use as an example. The schema though does not depend on any particular interpretation; we could use some other set of semantic assignments for English words, and the schema still would apply.
We could even say hypothetically that there's a natural language in which 'snow' stands for the thing we regard as fire and 'white' stands for the color we regard as black. The schema would still hold with that natural language taken as the standard one.
Therefore, "snow is white" is true because i) snow is white, ii) snow is named "snow" and white is named "white" — RussellA
No, (ii) is not included in the schema. The same point I just made The truth or falsehood of 'snow is white' is not dependent on 'snow' naming snow (precipitation...) and 'white' naming white (the chromaticity...). No matter what you say 'snow' denotes and no matter you say 'white' denotes, 'snow is white' is true iff the thing you set as the denotation of 'snow' has the property [extensional sense] that you set as the denotation of 'white'.
/
I hope to take time to carefully read your remarks about Putnam.