Solving equations has nothing to do with positing real ontological entities. — Terrapin Station
That they're consistent with GR doesn't make them a prediction of GR. We invented them so that they'd be consistent with GR, otherwise we'd need to retool our gravitational theory. — Terrapin Station
It follows from this lawful relation (i.e. Einstein's field equations) that whenever a spherical distribution of mass achieves a density such that it is contained within its Schwarzschild radius, then the escape velocity at the surface attains the speed of light. — Pierre-Normand
So the equations did exactly that - obliged us to posit ontologically real outcomes (of which black holes are one of many now empirically supported examples). — apokrisis
Another flat earther. — apokrisis
Not a flat earther, but a perfect circle denier. — Metaphysician Undercover
The Kerr geometry exhibits many noteworthy features: the maximal analytic extension includes a sequence of asymptotically flat exterior regions, each associated with an ergosphere, stationary limit surfaces, event horizons, Cauchy horizons, closed timelike curves, and a ring-shaped curvature singularity. The geodesic equation can be solved exactly in closed form. In addition to two Killing vector fields (corresponding to time translation and axisymmetry), the Kerr geometry admits a remarkable Killing tensor. There is a pair of principal null congruences (one ingoing and one outgoing). The Weyl tensor is algebraically special, in fact it has Petrov type D. The global structure is known. Topologically, the homotopy type of the Kerr spacetime can be simply characterized as a line with circles attached at each integer point.
Note that the Kerr geometry is unstable with regards to perturbations in the interior region. This instability means that although the Kerr metric is axis-symmetric, a black hole created through gravitational collapse may not be so.‹See TfD›[dubious – discuss] This instability also implies that many of the features of the Kerr geometry described above may not be present in such a black hole.‹See TfD›[dubious – discuss]
A surface on which light can orbit a black hole is called a photon sphere. The Kerr solution has infinitely many photon spheres, lying between an inner one and an outer one. In the nonrotating, Schwarzschild solution, with α=0, the inner and outer photon spheres degenerate, so that all the photons sphere occur at the same radius. The greater the spin of the black hole is, the farther from each other the inner and outer photon spheres move. A beam of light traveling in a direction opposite to the spin of the black hole will circularly orbit the hole at the outer photon sphere. A beam of light traveling in the same direction as the black hole's spin will circularly orbit at the inner photon sphere. Orbiting geodesics with some angular momentum perpendicular to the axis of rotation of the black hole will orbit on photon spheres between these two extremes. Because the space-time is rotating, such orbits exhibit a precession, since there is a shift in the {\displaystyle \phi \,} \phi \, variable after completing one period in the {\displaystyle \theta \,} \theta \, variable.
https://en.wikipedia.org/wiki/Kerr_metric
You latched on to a phrase in a way that shows you don't understand the physical argument. Relativity would model the gravitational curvature as perfectly spherical, yet the definition is still asymptotic - the approach to a limit. — apokrisis
Well, we differ in opinion clearly, because I think you will necessarily get a mistaken result if you start from the premise of the perfect symmetry, and work backward away from this, to describe something which is not a perfect symmetry. It's like starting from a false premise. — Metaphysician Undercover
I suppose on the same principle you object to rulers that pretend to be straight, and clocks that pretend to be regular. — apokrisis
But first we must figure out why the straight ruler is not giving an accurate measurement. — Metaphysician Undercover
the straight ruler wont tell you why the thing you are trying to measure is crooked — Metaphysician Undercover
So you don't think GR might help with that? — apokrisis
I suppose on the same principle you object to rulers that pretend to be straight, and clocks that pretend to be regular. — apokrisis
Not so.
Relativity was/is falsifiable, but has since been verified on several occasions. — jorndoe
I explained that I would object to using a straight ruler to measure a crooked object. — Metaphysician Undercover
So you keep avoiding my question of how you would actually measure crookedness. Is there any way other than comparing it to what it is most directly not? — apokrisis
Crookedness is defined in terms of a departure from straightness. — apokrisis
This is simply how measuring the world works. — apokrisis
Describing an object is completely different from measuring it. — Metaphysician Undercover
And so you change the subject yet again. — apokrisis
Sure, you can define crooked as not straight if you want. But there are all kinds of different ways that something can be crooked. It could be bent, twisted, curved, etc. — Metaphysician Undercover
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