The poster continues to substitute rhetoric for argument, utterly failing to engage in rational argumentation or inferential reasoning. — Leontiskos
1. A -> (B & ~B) {1}
2. A {2}
3. B & ~B {1, 2}
4. ~A {1}
— TonesInDeepFreeze
The poster continues to assert his baseless arguments without answering the question and providing the rule of inference he purports to use in order to arrive at conclusion (4). — Leontiskos
The poster seems to suffer from psychological delusions and grandiosity. When faced with simple questions he retreats into himself, opting for 3rd-person rhetorical strategies and failing to engage in inferential reasoning. — Leontiskos
The poster continues to evidence a significant difficulty in using fairly basic forum features, such as quotes. — Leontiskos
So many of your claims have already been debunked in this thread. The truth-table approach to reductio was dispatched almost ten pages ago! — Leontiskos
The poster is doing it again! Trying to discredit interlocutors by painting them with a brush "truth-functional", even after I had at least a few times addressed that.
For about the half-dozenth time:
I am not a "truth functionalist". I study and enjoy classical logic, and appreciate its uses. But I am interested in other logics. I do not say that classical logic is the only logic that can be studied, enjoyed and used.
But when classical logic is being discussed, especially critiqued, it is crucial to say what actually is the case with classical logic. And in bringing clarity to what classical logic actually is, one needs to explain. Providing such explanations does not make one a "truth functionalist". — TonesInDeepFreeze
If you want to bring clarity you should explain what inference you used to draw (4). — Leontiskos
Again, as I said, for concision we may state RAA [emphasis added] without conjunction elimination:
If Gu{P} |- Q and if Gu{P} |- ~Q, then G |- ~P
is equivalent with
If Gu{P} |- Q & ~Q , then G |- ~P
If Gu{~P} |- Q and if Gu{~P} |- ~Q, then G |- P
is equivalent with
If Gu{~P} |- Q & ~Q, then G |- P
So, in this case:
(version 1)
1. A -> (B & ~B) {1}
2. A {2}
3. B & ~B {1, 2}
4. ~A {1}
is equivalent with
(version 2)
1. A -> (B & ~B) {1}
2. A {2}
3. B & ~B {1, 2}
4. B {1, 2}
5. ~B {1, 2}
4. ~A {1} — TonesInDeepFreeze
I don't get to say:
P→Q
P
~Q
∴ Q {See truth table for 1, 2} — Leontiskos
P→Q
P
~Q
∴ Q {See truth table for 1, 2; avert eyes from 3 at all costs. I repeat: do not allow 3 a seat at the truth table!} — Leontiskos
As it happens, truth tables don't adjudicate contradictions. — Leontiskos
(The fact that you think this sort of thing can be adjudicated by a truth table is proof that non-truth-functionality is in your blind spot.) — Leontiskos
4.31 We can represent truth-possibilities by schemata of the following kind (‘T’ means ‘true’, ‘F’ means ‘false’; the rows of ‘T’s’ and ‘F’s’ under the row of elementary propositions symbolize their truth-possibilities in a way that can easily be understood):
4.4 A proposition is an expression of agreement and disagreement with truth-possibilities of elementary propositions.
— Tractatus
4.46 Among the possible groups of truth-conditions there are two extreme cases. In one of these cases the proposition is true for all the truth-possibilities of the elementary propositions. We say that the truth-conditions are tautological. In the second case the proposition is false for all the truth-possibilities: the truth-conditions are contradictory . In the first case we call the proposition a tautology; in the second, a contradiction.
I'll maintain that the cardinal step, to using truth tables as a device for determining tautology and contradiction, was taken by Witti....complete... — TonesInDeepFreeze
Yep.Meanwhile, may I take it that the point is made about tautologies? — TonesInDeepFreeze
I'll maintain that the cardinal step, to using truth tables as a device for determining tautology and contradiction, was taken by Witti. — Banno
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