If such objects existed in our inertial frame, light from them would reach us in finite time, so these objects don't exist in that frame, and thus the frame doesn't foliate all of spacetime. — noAxioms
For example, the current inertial frame of Earth won't do: There are objects beyond our event horizon (events from which light can never reach us even in infinite time). If such objects existed in our inertial frame, light from them would reach us in finite time, so these objects don't exist in that frame, and thus the frame doesn't foliate all of spacetime. — noAxioms
That coordinate system works great for large distances, but completely fails where there is large curvature of spacetime: black holes. Any such non-local foliation does not cover the events within the black hole, and thus do not constitute a foliation of all spacetime. — noAxioms
You've drawn flat Minkowski spacetime (with arbitrary inertial frame) in which light from any spatial location will reach any other location. That makes it an inappropriate model of the large scale universe where light that is currently say 17 GLY away will never get here, not in 17 billion years or ever.As you can see, any event can be located in an inertial frame, but only those events within our past light cone can be detected by us now. Events outside that cone are still in the reference frame but cannot influence us. — Kenosha Kid
You can still foliate reasonable gravitation in 'bent' Minkowski spacetime, but not black holes. So for instance, a device measuring absolute time here on Earth would run apparently faster than one on the surface of Saturn due to the lower gravitational potential here on Earth. The same device on a ship with relativistic absolute speed would similarly appear to run faster (than the clock next to it) than it would if the ship had low peculiar velocity.Gravitation can't be accurately described by inertial frames but require curvilinear coordinate systems. — Kenosha Kid
There's no requirement for light to reach any location from any other since there are very much cases where that does not occur. My point was that in an inertial frame, light can reach location X from Y given enough time, and thus such a model is not a model of our universe.I don't get this. Why would they have to reach us? — Mr Bee
If there is a boundary to an inertial frame, then event outside that boundary do not exist in that frame. An inertial frame does support cosmic expansion, but it does not support acceleration of that expansion. So given no such acceleration, there would be no event horizon and light will eventually get from location X to Y given time. And even locally, an inertial frame cannot foliate the interior of black holes, so it fails twice.The light will never reach us because of cosmic expansion, so the fact that we don't see them doesn't mean they don't exist.
There are indeed ways to do it with a single black hole, but you must assume the black hole is at some kind of privileged location. So consider 3 events: A clock is dropped into a black hole. Event A is that clock 1 second (measured on that clock) after passing the event horizon. The black hole is big enough that it survives at least one second. The rock is dropped from a hovering location outside, which shines light down on the dropped clock. At some point the last light is emitted from this location that will catch up to the dropped clock before it hits the singularity. Event B is that hovering location 1 second after that last light goes out.I'm not sure about that. As far as I know, any spacetime that doesn't allow for closed timelike curves is open to being sliced into global hypersurfaces.
You've drawn flat Minkowski spacetime (with arbitrary inertial frame) in which light from any spatial location will reach any other location. That makes it an inappropriate model of the large scale universe where light that is currently say 17 GLY away will never get here, not in 17 billion years or ever.
Earth has an event horizon, and Minkowski spacetime does not. — noAxioms
You can still foliate reasonable gravitration in 'bent' Minkowski spacetime, but not black holes. — noAxioms
So for instance, a device measuring absolute time here on Earth would run apparently faster than one on the surface of Saturn due to the lower gravitational potential here on Earth. The same device on a ship with relativistic absolute speed would similarly appear to run faster (than the clock next to it) than it would if the ship had low peculiar velocity. — noAxioms
1. Does black hole time travel increase or decrease Time ( I can't remember)? — 3017amen
2. Do black holes contribute to Multiverse theories at all? — 3017amen
My point was that in an inertial frame, light can reach location A from B given enough time, and thus such a model is not a model of our universe. — noAxioms
If there is a boundary to an inertial frame, then event outside that boundary do not exist in that frame. — noAxioms
There are indeed ways to do it with a single black hole, but you must assume the black hole is at some kind of privileged location. So consider 3 events: A clock is dropped into a black hole. Event A is that clock 1 second (measured on that clock) after passing the event horizon. The black hole is big enough that it survives at least one second. The rock is dropped from a hovering location outside, which shines light down on the dropped clock. At some point the last light is emitted from this location that will catch up to the dropped clock before it hits the singularity. Event B is that hovering location 1 second after that last light goes out.
Event C is at the location of the former black hole after it has evaporated.
Yes, you can come up with various schemes to order these three events, but do any of those schemes order all of spacetime? OK, C occurs after B since it is in the future light cone of B. That's easy. Not so easy with event A.
I'm not suggesting retrocausality anywhere. Event A is not causally connected with either B or C, so no objective ordering scheme is going to produce a contradiction unless B is in A's future but C is in A's past. — noAxioms
Time slows (is more dilated) when deep in a gravity well, So clocks on Earth for instance run objectively slower than say GPS clocks (which are very high up and not moving fast). Those GPS clocks are slowed due to their orbital motion, but the gravity effect is greater at that altitude. Clocks on the ISS run slower than the ones on the ground due to minimal gravitational potential difference in low orbit, coupled with significant dilation from the higher orbital velocity. So at an altitude of 1.5 R (R being Earth's radius), the two effects cancel out and orbiting clocks can be synced indefinitely with those on the ground.Two quick questions:
1. Does black hole time travel increase or decrease Time ( I can't remember)?
2. Do black holes contribute to Multiverse theories at all? — 3017amen
I don't really have the expertise to properly address this (hopefully someone like Kenosha Kid can chime in here and give his input). — Mr Bee
The rock is dropped from a hovering location outside, which shines light down on the dropped clock. — noAxioms
You don't comprehend my explanation, so I'll try to comprehend your vision.It's perfectly appropriate for that: that's just light further outside the light cone. It being further away just means its further away. Minkowski spacetime is not appropriate for gravity, though. — Kenosha Kid
There is no cosmic expansion under inertial spacetime. There is only an explosion of stuff from a point, with nothing moving at faster than c.I don't see how that is a consequence of a global inertial frame. Light may not reach us for other reasons unrelated to it, one of which is the cosmic expansion of the universe being faster than light. — Mr Bee
They are indeed not the same. The boundary of our inertial frame is much less than the 47 BLY radius of the observerable universe, and even less than the ~16 BLY distance to the event horizon. The current radius of our inertial frame must be 13.8 BLY because nothing outside that radius could have come from the big bang without moving faster than c, and nothing moves faster than c in an inertial frame.If there is a boundary to an inertial frame, then event outside that boundary do not exist in that frame.
— noAxioms
You seem to be mixing up the boundary of the observable universe with the "boundary" of an inertial frame, the latter of which I don't really understand. They are both not the same.
Your understanding here is fine. Nobody is proposing a closed timelike curve. Any foliation, objective or not, would preclude that.My understanding is that it is mainly spacetimes with closed timelike curves that preclude the existence of global hypersurfaces, but I haven't heard anything about black holes doing the same.
First of all, I meant dropping a clock, which seem more useful than dropping a glowing rock. I used a rock at first and neglected to change them all to 'clock'. But it moves like the rock: not under propulsion or anything.I got lost at:
The [clock] is dropped from a hovering location outside, which shines light down on the dropped clock.
— noAxioms
It's not clear what frame of reference we're in here. — Kenosha Kid
I've caused confusion. The rock and the dropped clock are the same thing. The space station can watch it fall in, but if it reads time T when it crosses the event horizon, then the space station will never see the clock read anything after T. It will appear from the space station to slow and approach but never reach T. Event B is that clock when it reads T+1.From the perspective of an observer outside the event horizon (with some magic blackholescope), the clock will accelerate toward the singularity and run slower and slower. Any photons emitted from the rock (which is getting further and further away from the clock) will still travel at the speed of light and catch up with the clock, because the clock cannot move at the speed of light.
Again, they are the same thing, so the clock indeed will eventually reach the abrupt end of time and tick it's last, so to speak. This is assuming the clock is a point device that isn't destroyed by excessive violence like tidal forces before it gets to the singularity.From the rest frame of the clock, it is in perpetual free fall. Eventually the rock will simply recede so far into the distance it cannot be detected.
The wiki site says it was emitted 13.4 billion years ago, but it could not have got far enough away in only 400M years for light to take that long. Of course, wiki isn't using inertial coordinates when making that statement, so kindly describe the situation in those terms. Where is the emission event? — noAxioms
I've caused confusion. The rock and the dropped clock are the same thing. The space station can watch it fall in, but if it reads time T when it crosses the event horizon, then the space station will never see the clock read anything after T. It will appear from the space station to slow and approach but never reach T. Event B is that clock when it reads T+1. — noAxioms
. It is at least highly intriguing that the only place where conditions approach those of the early (Big Bang) universe are the interiors of black holes, and maybe even moreso the fact that a time-reversed black hole (i.e. a white hole) looks eerily similar to the Big Bang itself. — Enai De A Lukal
GN-z11 is about 2/3 of the way to the edge of the visible universe. Immediately after inflation, the size of the visible universe was anywhere from a grain of sand to a city block, depending on your model. A 1 meter head start isn't going to get that object (or rather, the material that would eventually become it) out far enough to be 13.4 GLY away when that light is emitten only 400 MYr laterThe wiki site says it was emitted 13.4 billion years ago, but it could not have got far enough away in only 400M years for light to take that long. Of course, wiki isn't using inertial coordinates when making that statement, so kindly describe the situation in those terms. Where is the emission event?
— noAxioms
Right. So, first, there was a supposed stupendous inflation period in the early universe that cannot be described by any inertial frame. — Kenosha Kid
OK, you're allowed to give it more time, but how long do you want? It's going to take 13.4 billion years to get far enough away, at which point there's no time left to send the light back to us here.Second, it is unexpected that the galaxy would have formed 400M years after the big bang
Actually it does stop it. It's not a mystery, it's a physical impossibility in an inertial coordinate system for something to move 13.4 BLY away and then send a signal back, all in 13.8 BYr. Waving your hand around and spreading 'I don't know/it's a mystery' dust all over the place isn't a viable model.i.e. it is a cosmological and astronomical mystery but a) that doesn't stop it being 13.4 billion light years away from us when it did form
There are at least six kinds of multiverses discussed. Tegmark enumerated them as Level 1 (other Hubble spheres), Level 2 (other bubbles in eternal inflation theory), Level 3 (other quantum worlds), and Level 4 (other unrelated structures). There is also the Smolin evolutionary thing where the interiors of black holes are considered to be other universes. If Level 1 is our universe but spatially 'not here', then there should be a Level 0 which is our universe but temporally 'not now'. That's six at least.could multiverse theories be an attempt to explain causation prior to the Big Bang? — 3017amen
Whether it is interpreted as block or not seems immaterial. Look into eternal inflation theory. Wiki has a terse entry on it. I found a more comprehensive description in Tegmark's Mathematical Universe with some illustrations that help with visualization. There are other 'universes' that have different number of spatial and temporal dimensions, and the vast majority of them cannot produce complex physical states.As a very rudimentary example, what in theory, would exist outside of the block universe?
I need your opinion then. OK a foliation based on the perspective some outside observer cannot account for events beyond the event horizon, and thus seems to not to be a viable candidate for an objective foliation of all of spactime. Is there some other coordinate system that is actually up to the task? If not, is this a valid falsification of objective space and time such as is proposed by Lorentz Ether Theory? This is not even including those interpretations that additionally posit a preferred moment in time.Worse, at the event horizon, time dilation becomes so extremely that, from the perspective of the outside observer, events there do not ever occur- not even after an infinite amount of time has passed. — Enai De A Lukal
the current inertial frame of Earth won't do: There are objects beyond our event horizon (events from which light can never reach us even in infinite time). — noAxioms
A coordinate system doesn't propagate. You mean light propagates at c in a coordinate system. This is more or less true for an intertial coordinate system, with variation on speed due to changes in gravitational potential. So light from another star often gets to us at slightly greater than c due to most of the trip taking place in space at higher gravitational potential than we have here.the current inertial frame of Earth won't do: There are objects beyond our event horizon (events from which light can never reach us even in infinite time).
— noAxioms
I don't see why an absolute coordinate system would be obligated to propagate that the speed of light. — Banno
They do in some coordinate systems, but they don't have a particular position in our inertial frame.Hence, those events that are beyond our event horizon nevertheless might have a particular position in an absolute coordinate system.
No coordinate system works. That's been my point. Every choice leaves parts of spacetime unordered. As Enai puts it: There are always events that cannot be consistently assigned a spot on any choice of objective timeline.The answer to your question seems to me to be that any coordinate system might be set up as absolute; relativistic physics specifies how we translate from any frame to any other frame, so calling any frame of reference absolute becomes simply irrelevant.
A coordinate system doesn't propagate. — noAxioms
As Enai puts it: There are always events that cannot be consistently assigned a spot on any choice of objective timeline. — noAxioms
events inside the black hole cannot be consistently assigned a spot on any outside observers timeline... — Enai De A Lukal
Every choice leaves parts of spacetime unordered. — noAxioms
Actually it does stop it. It's not a mystery, it's a physical impossibility in an inertial coordinate system for something to move 13.4 BLY away and then send a signal back, all in 13.8 BYr. — noAxioms
I'm here to discuss my argument against absolute time, with people who know their physics sufficiently to comment productively on it. This is not that discussion. — noAxioms
What are your thoughts on the general idea that black holes preclude a global slicing of spacetime? I always assumed it was just closed timelike curves would make them impossible but noAxioms apparently thinks otherwise. — Mr Bee
No such transformation exists since the astronaut never crosses the event horizon, so there can be no transformation of events beyond that from either frame to the other.If someone outside the hole applies the appropriate transformations to their forever-falling astronaut, they will find that form the astronaut's perspective the fall is finite. — Banno
He cannot apply the transformation, which is what is meant by events that cannot be consistently assigned a spot on the outside observer's timeline. His events do not exist at all on that outside timeline.If the astronaut applies the appropriate transformation, they will find that for someone outside the hoel the fall takes forever - or more.
Exactly, which is why I say that inertial frames do not describe the universe.That is a limitation of inertial frames, not of the physical universe. — Kenosha Kid
The material/energy from which they are comprised very much did.Also, you seem to think that if we see light from a star 13.4B LY away, there must have been a time when that star was very close to us. That is not right. It didn't have to "move 13.4 BLY away and then send a signal back". Stars did not emerge from the big bang.
The material/energy from which they are comprised very much did. — noAxioms
Exactly, which is why I say that inertial frames do not describe the universe. — noAxioms
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