What then of the postulate that the relative velocity of light with respect to an object is "constant"? If I'm travelling in a spaceship with a given velocity, the relative velocity of light with respect to my spaceship will be 300,000 km/h. If I were then to alter my velocity, doesn't the velocity of light have to change accordingly so as to ensure that the relative velocity stays at a constant 300,000 km/h?
What gives? — TheMadFool
I don't fully understand how this works technically. But, metaphorically, I assume that Einstein realized that everything in space-time must be moving & changing relative to something infinite-eternal. Some astrologers viewed God or the Sun as the Eternal center about which everything else revolves. So, Einstein chose the speed of light, measured relative to Earthlings, to set as a mathematical constant to which other things can be compared. I don't know if he was thinking of the Sun analogy, but it makes a nice metaphor. :nerd:What then of the postulate that the relative velocity of light with respect to an object is "constant"? — TheMadFool
What then of the postulate that the relative velocity of light with respect to an object is "constant"? If I'm travelling in a spaceship with a given velocity, the relative velocity of light with respect to my spaceship will be 300,000 km/h. If I were then to alter my velocity, doesn't the velocity of light have to change accordingly so as to ensure that the relative velocity stays at a constant 300,000 km/h?
What gives? — TheMadFool
It's 300,000 km/sec. It's a speed, not a velocity.The great Albert Einstein postulated that the velocity of light is constant at approximately 300,000 km/h. This one postulate and maybe a few more is the allegedly the foundation of his theory of relativity, a theory that has withstood many attempts at disproof. So far so good. — TheMadFool
Per Einstein, no. Close, but not exactly 40. For instance, scale up the speed to say 0.2c and 0.6c, and the relative velocity of B with respect to A becomes 4/9 c, not 0.4c.Consider 2 cars, A and B, moving on the same practically straight freeway.
1. Situation 1: A is moving at 20 km/h north and B is moving 60 km/h north. The relative velocity of B with respect to A is 60 - 20 = 40 km/h.
Unintuitive, but no. Light speed (not velocity) remains at c relative to anything. This works out if you use the velocity addition formula instead of straight addition like you're doing all through the OP.What then of the postulate that the relative velocity of light with respect to an object is "constant"? If I'm travelling in a spaceship with a given velocity, the relative velocity of light with respect to my spaceship will be 300,000 km/h. If I were then to alter my velocity, doesn't the velocity of light have to change accordingly so as to ensure that the relative velocity stays at a constant 300,000 km/h?
And, the speed of light is not just a postulate. — tim wood
Light speed (not velocity) remains at c relative to anything. — noAxioms
There's no excuse for your ignorance on this - or for such an ignorant comment. — tim wood
That the speed of light is the same, relative to any object, was an Einsteinian postulate. — Metaphysician Undercover
It's 300,000 km/sec. It's a speed, not a velocity.
The postulate of SR is that that speed will be measured regardless the reference frame used. It doesn't actually posit that the speed actually IS frame invariant, just that it will be measured that way. — noAxioms
Per Einstein, no. Close, but not exactly 40. For instance, scale up the speed to say 0.2c and 0.6c, and the relative velocity of B with respect to A becomes 4/9 c, not 0.4c. — noAxioms
Small point. C varies in different media, as through water, and so forth. And, fun fact, when it is slowed through water, then phenomena like Cerenkov radiation actually propagates faster than the light. In a vacuum, though, C is just C. Youtube for lots of videos on these topics. — tim wood
Ok but once you have a frame of reference it becomes relative velocity right? I mean the speed has to be relative to something. — TheMadFool
c = (c - a)/(1 - a/c) = approximately c = c - a where c is the velocity of light. c = c - a is a contradiction! — TheMadFool
light has the same speed relative to anything. — Pfhorrest
That's when the object's at relative rest. No problem with that.Not when a = 0, and 'approximately c' = c - a precisely when a = 'approximately 0', i.e. nonrelativistic speeds. (All nonrelativistic speeds are 'approximately 0' on the scale of relativistic speeds). — Pfhorrest
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