There is if motion is continuous, which is a premise of the argument that gives rise to the paradox. If motion is discrete then the paradox wouldn't arise. — Michael
The problem here is equating continuity with infinite divisibility, as if space and time consisted of infinitely many points and instants, respectively. The reality is that there are no actual points, just continuous space; and there are no actual instants, just continuous time. An infinitesimal distance can be traveled in an infinitesimal interval of time. A finite distance can be traveled in a finite interval of time. — aletheist
You have it exactly backwards - the paradox only arises by insisting that space is made up of infinitely many points, and time is made up of infinitely many instants. When we recognize that both space and time are continuous, the paradox dissolves - there are no intermediate points that I have to "touch" while moving from defined point A to defined point B in a finite interval of time, just like I do not need to count any intermediate numbers in order to get from 1 to 2. — aletheist
If space is continuous then we can plot infinitely many points in it, so I don't understand your objection. — Michael
And I don't understand your distintion between infinite divisibility and continuity. — Michael
We can plot infinitely many points, but we do not have to plot any points between the two of interest. In other words, there are infinitely many potential points between any two actual points, but the only other actual points are the ones that we arbitrarily define. We can count from 1 to 2 in one step, in two steps, or in any other discrete number of steps; it is entirely up to us, and there is certainly no requirement to count all of the rational numbers in between. — aletheist
I have to count every rational number (in sequential order) between 1 and 2. I'm not allowed to just skip ahead to some arbitrary point. — Michael
You are already being arbitrary by only counting all of the rational numbers between 1 and 2. What is your excuse for not counting all of the real numbers between 1 and 2 - i.e., also including irrational numbers? — aletheist
The task is to count every rational number between 1 and 2. — Michael
My coordinate system only uses the rational numbers. So I ask again; what coordinate does it pass through first? — Michael
No, the task is to move from point A to point B. You are mathematically modeling it as counting every rational number between 1 and 2. I am challenging the fundamental assumption of your model. I can count from 1 to 2 without counting any other numbers in between. Likewise, I can move from point A to point B without touching any points in between, because there are no (actual) points in between. — aletheist
My coordinate system only uses the integers. After all, units of physical measurement are completely arbitrary. — aletheist
Again your picture is muddled. The task you set was to count the rationals; now you have slid from that to finding the first rational. — Banno
There is no first rational between 1 and 2. But there are exactly a denumerably infinite number of rationals between one and two.
No, when I say that the task is to count the rational numbers between 1 and 2 I'm not talking about the task to move from point A to point B; I'm talking about the task to count the rational numbers between 1 and 2. — Michael
My coordinate system only uses the rational numbers. So I ask again; what coordinate does it pass through first? — Michael
You're overthinking it.
½ + ¼ + ⅛...=1 — Banno
A true continuum is infinitely divisible into smaller continua; it is not infinitely divisible into discrete individuals. — aletheist
My coordinate system only uses the rational numbers. So I ask again; what coordinate does it pass through first? — Michael
My coordinate system only uses the rational numbers. So I ask again; what coordinate does it pass through first? — Michael
It appears to me, like no matter how far you go you'll always be a fraction short of 1. — Metaphysician Undercover
It just doesn't work that way. You can never count to the end of an infinite series of numbers. — Michael
Convert 1/3 to a decimal, then multiply it by 3. Is the result 1, or an infinitesimal fraction short of 1? — aletheist
Can't be done. — Metaphysician Undercover
What does that have to do with my question? — Metaphysician Undercover
So you are assuming that you can be done doing something an infinite amount of times? — Metaphysician Undercover
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