Assume to reach a contradiction that there exists a program Halt(P, I) that solves the halting problem, — Prof Kirk Pruhs
In the other thread I suggested that the analogue would be "Will Program Z loop forever if fed itself as input?" — Banno
On The Electrodynamics Of Moving Bodies? He talks about empty space. No mention of void in this English translation.General relativity is about gravity and acceleration. Special relativity starts with a thought experiment that shows that in a void, with one object stationary and one object moving at a constant speed, there's no fact of the matter about which one is actually stationary and which one is moving. — frank
There was before Newton.There's no void. — frank
Einstein used it — frank
Austin, especially in Other Minds, addresses "real".
But is it a real one? When you ask if it is real, what are you sugesting? No, it's a fake; it's an illusion; it's a forgery; it's a phoney, a counterfeit, a mirage... What is real and what isn't is decided in each case by contrast; there is no single criteria. — Banno
When it finds a contradiction is derived by a decision problem
then it is this decision problem that must be rejected. — PL Olcott
Yes, in the example argument above, Z is shown to imply a contradiction, and so is to be rejected.When it is contradicted that some H can correctly determine
the halt status of the direct execution of every D, then this
definition of the problem is rejected as incorrect. — PL Olcott
Yes this applies generally. — PL Olcott
The flaw is that the whole notion of decision problem undecidability
is inherently flawed in that it requires the logically impossible. — PL Olcott
The Halting Problem is:
INPUT: A string P and a string I. We will think of P as a program.
OUTPUT: 1, if P halts on I, and 0 if P goes into an infinite loop on I.
Theorem (Turing circa 1940): There is no program to solve the Halting Problem.
Proof: Assume to reach a contradiction that there exists a program Halt(P, I) that solves the halting problem, Halt(P, I) returns True if and only P halts on I. The given this program for the Halting Problem, we could construct the following string/code Z:
Program (String x)
If Halt(x, x) then
Loop Forever
Else Halt.
End.
Consider what happens when the program Z is run with input Z
Case 1: Program Z halts on input Z. Hence, by the correctness of the Halt program, Halt returns true on input Z, Z. Hence, program Z loops forever on input Z. Contradiction.
Case 1: Program Z loops forever on input Z. Hence, by the correctness of the Halt program, Halt returns false on input Z, Z. Hence, program Z halts on input Z. Contradiction.
End Proof. — Prof Kirk Pruhs
An agument cannot possibly be valid if it contains a fatal flaw. — PL Olcott
Oh, good.No, I don't have things in themselves in mind here. — Manuel
and yet see the argument as valid.requiring the logically impossible is an invalid requirement — PL Olcott
...truth as it reveals itself to us... — Manuel
Nothingness is inconceivable by definition. — Tom Storm
So you can't have the very large stuff but you can have the small stuff? Then don't worry about the very large stuff.Truth and knowledge are very large concepts... — Vera Mont
