As I noted earlier in response to Tones' reductio, a reductio is an indirect proof which is not valid in the same way that direct proofs are. You can see this by examining your conclusion. In your conclusion you rejected assumption (2) instead of assumption (1). Why did you do that? In fact it was mere whim on your part, and that is the weakness of a reductio.*
* A reductio requires special background conditions. In this case it would require the background condition that (1) is more plausible than (2). — Leontiskos
I think I finally solved my own problem. When translating it to natural language, I was misplacing the associativity of the → operator in this case.
So ¬(A → (B∧ ¬B)) is the same as (¬A) → (B∧ ¬B), which may be read as "Not-A implies a contradiction", it can't read as "A does not imply a contradiction". We would have to say something like A ¬→ (B∧ ¬B), which most checkers will reject as improper formatting, so we just say A → ¬(B∧ ¬B), which can be read as "A implies not-a-contradiction", more naturally as "A does not imply a contradiction". — Lionino
"If A implies B & ~B, then A implies a contradiction" is true, but it is a statement about the sentences, not a translation of them. — TonesInDeepFreeze
Or if you think it is only truth-functional if it fits in a truth-table: — Banno
'non-particular' is your word. It's up to you to say what you mean by it. — TonesInDeepFreeze
(3) "B & ~B" is a particular contradiction, not just "a contradiction". Even though all contradictions are equivalent, a translation should not throw away the particular sentences that happened to be mentioned. — TonesInDeepFreeze
Thus when Banno says that a contradiction (b∧¬b) is false, does he mean that it is false or that it is FALSE? — Leontiskos
↪Leontiskos I solved my main problem just right above. — Lionino
Does this support my claim that what is at stake is something other than a material conditional? The negation does not distribute to a material conditional in the way you are now distributing it. — Leontiskos
But for the record I do accept this as a valid rhetorical move. However when it comes to propositional logic, from
P1: A
P2: A→contradict
The conclusion can be whatever we want, from explosion — Lionino
I understand that you'd think that B∧¬B should be able to be replaced by any proposition P, but that is not the case.
Example:
(A∧(B∧¬B))↔(B∧¬B) is valid
But (A∧C)↔C is invalid. — Lionino
...so I think now it is a bit more clear why ¬(a→(b∧¬b)) is True only when A is True, the second member is always False and the or-operator returns True when at least one variable is True. — Lionino
(a→b) ↔ (¬a∨b)
¬(a→b) ↔ ¬(¬a∨b)
However (a∨b) and ¬(¬a∨b) aren't the same
So ¬(a→b) and (a∨b) aren't the same
(a→(b∧¬b)) ↔ (¬a∨(b∧¬b))
¬(a→(b∧¬b)) ↔ ¬(¬a∨(b∧¬b))
(¬a→(b∧¬b)) ↔ ¬(¬a∨(b∧¬b))
Since ¬(¬a∨(b∧¬b)) is the same as (a∨(b∧¬b))
(¬a→(b∧¬b)) ↔ (a∨(b∧¬b)) — Lionino
(3) A ... toward a contradiction — TonesInDeepFreeze
The main problem for me is, why can we read a→(b∧¬b) as "a implies a contradiction" but not ¬(a→(b∧¬b)) as "a does not imply a contradiction? — Lionino
I think I finally solved my own problem. When translating it to natural language, I was misplacing the associativity of the → operator.
So ¬(A → (B∧ ¬B)) is the same as (¬A) → (B∧ ¬B) — Lionino
Suppose that the logic concerned is weaker than Peano arithmetic, such that it can prove its own consistency. Then in this case, a proof of ¬¬a metalogically implies that ¬a isn't provable, i.e that a does not imply a contradiction.
But if the axiomatic system contains Peano arithmetic such that the second incompleteness theorem holds, then a proof of ¬¬a does not necessarily imply the absence of a proof of ¬a, since Peano arithmetic cannot prove its own consistency. — sime
The negation of a contradiction is always true, and being true it is implied by anything, true or false. — Count Timothy von Icarus
In a normal conversation, we might ask "but what if A really only implies B and not B and not-B?" Or conversely: "what if A only implies not-B but does not actually imply B?" But the way implication works here it is not an additional premise we can reject, we don't assign a truth value to it except in virtue of the truth values of A and B themselves. — Count Timothy von Icarus
However, there is a quite good reason not to do this in symbolic logic. Once you start getting into "what 'really' entails what," you get into judgement calls and a simple mechanical process won't be able to handle these. — Count Timothy von Icarus
But of course, you still need judgement to make sure your statements aren't nonsense, so you just kick that problem back a level. A proof from contradiction is only going to be convincing if we believe that A really does imply both B and not-B. I know plenty of skepticism has been raised against proofs from contradiction in general, outside of this issue, but for many uses they seem pretty unobjectionable to me. — Count Timothy von Icarus
Every time we make an inference on the basis of a contradiction a metabasis eis allo genos occurs (i.e. the sphere of discourse shifts in such a way that the demonstrative validity of the inference is precluded). Usually inferences made on the basis of a contradiction are not made on the basis of a contradiction “contained within the interior logical flow” of an argument. Or in other words, the metabasis is usually acknowledged to be a metabasis. As an example, when we posit some claim and then show that a contradiction would follow, we treat that contradiction as an outer bound on the logical system. We do not incorporate it into the inferential structure and continue arguing. Hence the fact that it is a special kind of move when we say, “Contradiction; Reject the supposition.” In a formal sense this move aims to ferret out an inconsistency, but however it is conceived, it ends up going beyond the internal workings of the inferential system (i.e. it is a form of metabasis). — Leontiskos
Where — Lionino
1. A→(B∧¬B) assumption
2. A assumption
3. B∧¬B 1,2, conditional proof
4. ~A 2, 3 reductio — Banno
No, you asked for the rule of inference from classical logic - it's right there, common knowledge in wikipedia. — flannel jesus
Well, if something results in a contradiction, we are able to rule it out, aren't we? — Lionino
Perhaps my idea is that if someone engages in these sorts of inferences then there should be added an asterisk to their conclusion on account of the fact that this form of metabasis is highly questionable. I mostly want attention to be paid to what we are doing, and to be aware of when we are doing strange things. — Leontiskos
At one point we may find ourselves in contradiction and if all we do is hold to two contradictory principles we'll do nothing but compute them (if that is our true desire), and die. — Moliere
Truth be told, PDE is an unwieldy principle. There are cases (such as the hysterectomy) where it seems to obviously apply, but it has often been noted that in other cases the principle can be easily abused. Our topsy-turvy discussion in the other thread got at some of the nuance involved. — Leontiskos
This is the sort of ambiguity that seems to always follow the PDE, namely cases which are hard to decide. So this is in line with the tradition of the PDE, and I think it is good to recognize such limitations. — Leontiskos
in classical propositional logic contradictions are false. — Banno
1. A→(B∧¬B) assumption
2. A assumption
3. B∧¬B 1,2, conditional proof
4. ~A 2, 3 reductio — Banno
...Or in other words, the metabasis is usually acknowledged to be a metabasis. As an example, when we posit some claim and then show that a contradiction would follow, we treat that contradiction as an outer bound on the logical system. We do not incorporate it into the inferential structure and continue arguing. Hence the fact that it is a special kind of move when we say, “Contradiction; Reject the supposition.” In a formal sense this move aims to ferret out an inconsistency, but however it is conceived, it ends up going beyond the internal workings of the inferential system (i.e. it is a form of metabasis). — Leontiskos
I think calling them both assumptions has led to your confusion. Premise 1 is more of a GIVEN than an assumption. — flannel jesus
I don't think there is any mystery around (A→(B∧¬B)) |= ¬A, if something implies a contradiction we may say it is false. — Lionino
A reductio is as much a proof in classical propositional logic as is modus tollens. — Banno
I am concerned that logicians too often let the tail wag the dog. The ones I have in mind are good at manipulating symbols, but they have no way of knowing when their logic machine is working and when it is not. They take it on faith that it is always working and they outsource their thinking to it without remainder. — Leontiskos
I read the whole post. — AmadeusD
Before tenancy enforcement infrastructure, you would be an absolute moron to try to 'force' your landlord's hand. — AmadeusD
The point here is not that the landlord must, of absolute necessity, honor his promise. That is a strawman form of obligation. The point is that it is rational for him to do so, and therefore it is rational for you to invoke the promise when he says you underpaid, and therefore it is rational for you to write the check for $975 in the first place. — Leontiskos
The reductio shows that A→(B∧¬B)⊢~A. As ↪hypericin pointed out. — Banno
As I noted earlier in response to Tones' reductio, a reductio is an indirect proof which is not valid in the same way that direct proofs are. You can see this by examining your conclusion. In your conclusion you rejected assumption (2) instead of assumption (1). Why did you do that? In fact it was mere whim on your part, and that is the weakness of a reductio.*
* A reductio requires special background conditions. In this case it would require the background condition that (1) is more plausible than (2). — Leontiskos
Simply because I matched your example — Banno
Is he being irrational in this? Is he deluded and engaged in bullshit? — Leontiskos
Indeed, while your second example is a case of modus tollens, the first is not. — Banno
1. A→(B∧¬B) assumption
2. A assumption
3. B∧¬B 1,2, conditional proof
4. ~A 2, 3 reductio — Banno
Don't put the blame for your poor notation on to me. — Banno
Because legal support exists. Otherwise, no one in their right mind would go to a landlord and try to hold them to their word. — AmadeusD
Then suppose you invoke the promise and he says, "Oh sorry, I forgot about that. Never mind."
Is he being irrational in this? Is he deluded and engaged in bullshit?
You say that his word is good enough to write the check for $975, but it is not good enough for you to invoke when he says you underpaid. You are contradicting yourself. You wrote the subsidized check on the basis of a promise - a real promise that involved obligations. Without those obligations it would make no sense to write the subsidized check, and given the promise it makes no sense not to invoke it when he says you underpaid.
The point here is not that the landlord must, of absolute necessity, honor his promise. That is a strawman form of obligation. The point is that it is rational for him to do so, and therefore it is rational for you to invoke the promise when he says you underpaid, and therefore it is rational for you to write the check for $975 in the first place.
This sort of thing happens all the time in real life. Compare this to a different person who writes a check for $975 for no reason. Do they have recourse? Of course not. They are in an entirely different situation. The only difference between the two cases is an obligation. — Leontiskos
You think the two propositions logically imply ~A? It seems rather that what they imply is that A cannot be asserted. — Leontiskos
You could also put this a different way and say that while the propositions ((A→(B∧¬B)) and (B∧¬B) have truth tables, they have no meaning. They are not logically coherent in a way that goes beyond mere symbol manipulation. We have no idea what (B∧¬B) could ever be expected to mean. We just think of it, and reify it as, "false" - a kind of falsity incarnate.*
* A parallel equivocation occurs here on 'false' and 'absurd' or 'contradictory'. Usually when we say 'false' we mean, "It could be true but it's not." In this case it could never be true. It is the opposite of a tautology—an absurdity or a contradiction. — Leontiskos
Your loss. — Banno
Then the thread is in erorr. (p ^ ~p) is false in classical propositional logic. — Banno
Whether or not we affirm the negation of the consequent... — Leontiskos
Nowhere in that post do you affirm (B∧¬B). — Banno
As has been explained at length, in classical propositional logic contradictions are false. — Banno
As has been explained, in classical logic a contradiction is false. — Banno
Each of these systems sets out different ways of dealing with truth values. How the truth value of a contradiction is treated depends on which of these systems is in play.
Asking, as you do, how to treat the truth value of a contradiction apart from the system that sets out how a truth value is to be dealt with makes little sense. It does not make much sense to speak of "the notion of contradiction in its entirety". — Banno
If this is the nub then the problem is, as I said earlier, that truth-functional logic does not give us any instruction for how to handle contradictions. — Leontiskos
As has been explained, in classical logic a contradiction is false. — Banno
Because he told me to, and it's rational to pay less if the person asking you for money asks for less. — Michael
Then suppose you invoke the promise and he says, "Oh sorry, I forgot about that. Never mind." — Leontiskos
You say that his word is good enough to write the check for $975, but it is not good enough for you to invoke when he says you underpaid. You are contradicting yourself. You wrote the subsidized check on the basis of a promise - a real promise that involved obligations. Without those obligations it would make no sense to write the subsidized check, and given the promise it makes no sense not to invoke it when he says you underpaid. — Leontiskos
Another side of accidents that touches upon consequences well beyond our view is reflected in Aristotle saying there could be no science of them. That is oddly echoed in Chaos theory and the delicate efficacy of the butterfly effect. The big garden is not being tended. — Paine
There doesn't have to be a standard for there to be a spectrum. — Pantagruel
I personally know lots of people that live their lives recklessly and whose "intentions" routinely cause all kinds of havoc and produce all kinds of "unintended consequences". — Pantagruel
I think Aristotle's mean is very important. People think happiness is about chasing pleasures and avoiding pains, but they also fail to observe the mean in explicitly moral thinking. For example, I was recently having a discussion with Joshs over his idea that all blame/culpability should be eradicated from society (link). This is a common contemporary trope, "Blame/culpability is bad, therefore we should go to the extreme of getting rid of it altogether" (Joshs takes the culturally popular route of saying that everyone is always doing their very best, and therefore it is illogical to blame anyone for anything).
For Aristotle it is never that simple. We can't just run to the extreme and call it a day. Things like blame and anger will involve a mean, and because of this there will be appropriate and inappropriate forms of blame and anger. The key is learning to blame and become angry when we ought to blame and become angry, and learning not to blame and become angry when we ought not blame and become angry. — Leontiskos
But, as my second phrase in this post, I got confused as to whether ¬(a→(b∧¬b)) means a variable that is in contradiction with (a→(b∧¬b)) or simply that (a→(b∧¬b)) is False. — Lionino
¬(a→(b∧¬b)) is only ever True (meaning A does not imply a contradiction) when A is True. But I think it might be we are putting the horse before the cart. It is not that ¬(a→(b∧¬b)) being True makes A True, but that, due to the definition of material implication, ¬(a→(b∧¬b)) can only be True if A is true. — Lionino
When are we supposed to reduce a contradiction to its functional truth value, and when are we supposed to let it remain in its proposition form? The mind can conceive of [claims] like (b∧¬b) and ¬(b∧¬b) in these two different ways, the manner in which we conceive of them results in different logical outcomes, and symbolic logic provides no way of adjudicating how the [claims] are to be conceived in any one situation. — Leontiskos
If (a→b)∧(a→¬b) is False, ¬A is False, so A can be True or not¹. — Lionino
What is the definition 'analogical equivocity'? — TonesInDeepFreeze
Isn't this a fairly big problem given that (¬¬A↔A)? I take it that this is the same thing I have pointed out coming out in a different way? Namely the quasi-equivocation on falsity? — Leontiskos
Around a third of folk hereabouts who have an interest in logical issues cannot do basic logic. — Banno
If (a→b)∧(a→¬b) is False, ¬A is False, so A can be True or not¹. — Lionino
But (a→b)∧(a→¬b) being False simply means that A does not imply a contradiction, it should not mean A is True automatically. — Lionino
As noted in my original post, your interpretation will involve Sue in the implausible claims that attend the material logic of ~(A → B), such as the claim that A is true and B is false. Sue is obviously not claiming that (e.g. that lizards are purple). The negation (and contradictory) of Bob's assertion is not ~(A → B), it is, "Supposing A, B would not follow." — Leontiskos