why would they imagine someone saying that? — flannel jesus
In the case where there's 2 blue, a blue eyed person sees one blue eyed person, 2 brown eyed people, so he thinks what? How does he reason? — flannel jesus
This step in the reasoning doesn't ever get off the ground. — flannel jesus
A3 only works if you know that the blue eyed person you see knows green sees blue. But you don't know that he knows that. — flannel jesus
There is a hidden assumption that everyone arrives at the island at the same time, and can all see each other at that time. — hypericin
Everyone can see everyone else at all times [and] everyone on the island knows all the rules in this paragraph.
When b>=3, you absolutely DO know that. — hypericin
michael can't prove it for the case of 2. — flannel jesus
I can't explain this any simpler than I already have, so I'm not going to keep trying. — Michael
So it's explicit that everyone can see everyone else and knows that everyone can see everyone else, and implicit that new people don't just randomly appear or disappear — Michael
The Guru is allowed to speak once (let's say at noon), on one day in all their endless years on the island. — flannel jesus
Maybe they were literally there forever. — hypericin
Have you deduced your own eye color? — flannel jesus
No, because this is one of those n=2
=
2
scenarios that I explicitly accept doesn't always work. — Michael
I said it works if there are 2 brown and 2 blue. I didn't say it works if there is 1 blue, 2 brown, and 2 green. — Michael
It would only work for n=3 if it did work for n=2. — flannel jesus
Get involved in philosophical discussions about knowledge, truth, language, consciousness, science, politics, religion, logic and mathematics, art, history, and lots more. No ads, no clutter, and very little agreement — just fascinating conversations.