We should meet. There are simple games I should like to engage you in, for money.

Research some elementary probability theory. E.g., the three dice problem is resolved by considering all the ways - the permutations - they can fall. Count them up, and the count will give you the odds.

Anything could happen. You insist that out of 3 dice rolls, rolling the exact same number all three times is just as likely as any other scenario? So, rolling a die 50 times and getting the same number all 50 times- in a row- is just as likely as not? How come it never happens then.

As likely as any other permutation. Each is 1 in 6x6x6 = 216. But don't confuse permutations and combinations. Do you really not know any of this stuff?

So, long story short the odds of rolling a single number 50 times in a row is less than not. We're hardly at odds here it would seem. What's your deal?

the odds of rolling a single number 50 times in a row is less than not. — Outlander

Eh?

My calculator says that the chance of rolling a single number 50 time in a row is abut 1 in 1.347 x 10^38. At a second per throw, I've got that at once in about 4.25 x 10^30 years. Did I make a mistake?

To put it another way, if you were forced to make a bet of three scenarios involving a die rolled three times. Which would you choose? A.) Each roll would be different. B.) Two rolls in a row would be the same. C.) All three rolls would be the same. — Outlander

As I see it, these are equiprobable scenarios each with a probability of 1/216. Sorry, I think I missed your point.