What scenarios doesn't frequentism work for? — Down The Rabbit Hole
Just a nitpick. Not every f(x) function is bijective. — Lionino
So (B∨¬B) is False, it is always the case that ¬B. — Lionino
However, reading (A implies notB) as "something other than B (caveat: also) follows from A". would be consistent with "B follows from A", because it would not deny that B also follows from A. — Janus
You edited your posts after reading the arguments of Michael and Igitur :lol: — javi2541997
Because you claim A can’t be a liar emphatically. — javi2541997
Am I missing something in that attempt to use logic? — javi2541997
But I was wondering what happened to A. — javi2541997
Some claim he is ambiguous, others he is contradictory. — javi2541997
No, B is the ambiguous person given the ambiguity of the phrase "I sometimes tell the truth". — Michael
Then B is always false and ambiguous — javi2541997
But what happens to A? — javi2541997
Person A claims person B always tells the truth.
Person B claims person B (himself) sometimes tells the truth.
Person C claims person B always lies.
Secondly, I want to solve this riddle. Who is the liar? — javi2541997