So now you are making use of a private rule... this (indicating the qual) is red...
And how can we say that what you pick out by "this" is the same as what I pick out?
I don't see that question as having any significance. — Banno
Not everyone agrees with Wittgenstein. If you don't know what red means, how could you use the word "red"? If you are a colour blind, how could you tell red objects? For you being able to use the word red means that you know what you mean by red from your experience of seeing red via your perception, and folks describing red objects as red. — Corvus
Well if your are to convince me of this I'd first have to be convinced that you understood Wittgenstein.Wittgenstein was wrong. — Corvus
... and so on. If I ask for the red pen, and they hand me the red pen, that's not metaphorical, nor is it merely rhetorically, and it certainly isn't idiomatic. It's pretty much literal and extensional.They could be using the word red metaphorically... — Corvus
Quite so; if someone referred to "the sensation S" for themselves alone, then the qual is private; and if they do it for others, isn't it just the colour red? Here's the problem with qualia: if they are private, then they are outside of our discourse, and if they are public, they are just our common words for this or that.This seems to conflate several issues. Why is my description of my red quale a private rule? What would be the (correct, presumably) use of a public rule to describe the quale? I'm not seeing the alternative. — J
Rather we play with them, ask for the red block, offer them a lolly - but only the red one, and so on. We teach them to use the word. Then there is no "why?" as the task is of forthright interest.? What do we teach a child when we teach them color names? "When you point to that, say 'red'?" And if the child replies, "Why?" what do we say? — J
...and it doesn't matter!. Becasue what counts here is the use!As for whether you and I are naming the same quale, wouldn't the answer be: Conceivably we aren't, — J
If one says one can use words without knowing its meanings, then he is wrong, whoever he is.Well if your are to convince me of this I'd first have to be convinced that you understood Wittgenstein. — Banno
They must have been acquainted with something other than "red" to be able to do that by habit or guessing. That doesn't mean they know what "red" is. Their use of "red" could be based on the high chance of fluke guessing.... and so on. If I ask for the red pen, and they hand me the red pen, that's not metaphorical, nor is it merely rhetorically, and it certainly isn't idiomatic. It's pretty much literal and extensional. — Banno
...and to admit lobsters only after boiling.
Different persons growing up in the same language are like different bushes trimmed and trained to take the shape of identical elephants. The anatomical details of twigs and branches will fulfil the elephantine form differently from bush to bush, but the overall outward results are alike. — Word and Object
We have a part agreement here, which is a rare event.I agree. But to know a word is to use it, and to us either is to know it. — Banno
Actually it is difficult for me to imagine what colour blind would be like without being one myself, hence the point was purely from inference. You could be right. Please carry on....but nor does it mean that they do not! — Banno
Upon the contrary-to-fact conditional depends in turn, for example, this definition of solubility in water: To say that an object is soluble in water is to say that it would dissolve if it were in water. In discussions of physics, naturally, we need quantifications containing the clause ‘x is soluble in water’, or the equivalent in words; but, according to the definition suggested, we should then have to admit within quantifications the expression ‘if x were in water then x would dissolve’, that is, ‘necessarily if x is in water then x dissolves’. Yet we do not know whether there is a suitable sense of ‘necessarily’ into which we can so quantify? — p 158-9
That is, and here I'm grossly overgeneralising, the extension. — Banno
I'm not seeing a problem with that. It might have been that beads 4,5, and 6 were the red beads. In which case, in that domain, "...is red" would be extensionally equivalent to {4,5,6} instead of {1,2,3}. And an extensional sentence about the red beads would have the same truth value as an extensional sentence about the beads {4,5,6}, and passes the test of substitution.How do we make coherent a situation where the extension remains the same but the color changes? — J
If planets and planètes have the same extension, then "The number of planets is greater than 7" means the same thing as "The number of planètes is greater than 7". Is there any intermediary step that would show this to be true? — J
The list of planets just is the "meaning" of both Planets and Planètes, and so since their number is greater than seven, both the English and French sentences are true.Planets = Planètes = {Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune} — Banno
without further explanation. That is, if planets and planètes have the same extension, then "The number of planets is greater than 7" means the same thing as "The number of planètes is greater than 7" without further ado.The number of the planets > 7 = "Le nombre de planètes > 7
It's not that use reduces to extension, but that the use of a (proper) name is it's extension - what it refers to. — Banno
We want to say that there is more to being red than being {1,2,3}; but note that that "more" is intensional rather than extensional — Banno
what does that tell us about "red"? — J
So we need necessity in order to do physics; but we must debar it from logic. A difficult path to tread. — Banno
Not something with which I am familiar. But in intuitionistic type theory, isn't a theorem synthetic if its truth depends on constructive proof rather than mere definitions? That is, not all synthetic theorems contain existential quantifiers. Consider "Every red bead appears before every blue bead on the string", which is not analytic, which must be determined by inspecting the arrangement of beads, and which uses universal quantification only. I may be misunderstanding your point, but being synthetic is not dependent on existential quantification only. However if your point is just that theorems containing an existential quantification are always synthetic because they require constructive proof, then yep. — Banno
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